Filter computes outSegments using following formulas: $$\mathbf {outSegments}[0].x_{begin} = \mathbf {inSegment}.x_{begin}$$ $$\mathbf {outSegments}[0].y_{begin} = \mathbf {inSegment}.y_{begin}$$ $$\mathbf {outSegments}[0].x_{end} = \mathbf {inSegment}.x_{begin} + \Delta x$$ $$\mathbf {outSegments}[0].y_{end} = \mathbf {inSegment}.y_{begin} + \Delta y$$ $$\mathbf {outSegments}[i].x_{begin} = \mathbf{outSegments}[i-1].x_{begin} + \Delta x $$ $$\mathbf {outSegments}[i].y_{begin} = \mathbf{outSegments}[i-1].y_{begin} + \Delta y $$ $$\mathbf {outSegments}[i].x_{end} = \mathbf{outSegments}[i-1].x_{end} + \Delta x $$ $$\mathbf {outSegments}[i].y_{end} = \mathbf{outSegments}[i-1].y_{end} + \Delta y $$ $$ i = 1, 2, .., \mathbf {inCount} - 1 $$ where $$\Delta x = \frac {\mathbf{inSegment}.x_{end} - \mathbf{inSegment}.x_{begin} }{\mathbf{inCount} }$$ $$\Delta y = \frac {\mathbf{inSegment}.y_{end} - \mathbf{inSegment}.y_{begin} }{\mathbf{inCount} }$$

Assume segment described with two points:

• Start point P(0, 0)
• End point Q(3, 6).

To split segment into three parts of equal length, set inCount = 3.
Result will be as follows: $$\mathbf {outSegments}[0]=\vec{P_1Q_1}=[1, 2] \quad \mathbf {outSegments}[1]=\vec{P_2Q_2}=[1, 2] \quad \mathbf {outSegments}[2]=\vec{P_3Q_3}=[1, 2]$$